Files
python-bpf/examples/execve3.py
2025-09-12 04:26:27 +05:30

77 lines
1.5 KiB
Python

from pythonbpf import bpf, map, section, bpfglobal, compile
from pythonbpf.helpers import ktime
from pythonbpf.maps import HashMap
from ctypes import c_void_p, c_int64, c_int32, c_uint64
@bpf
@map
def last() -> HashMap:
return HashMap(key_type=c_uint64, value_type=c_uint64, max_entries=3)
@bpf
@section("tracepoint/syscalls/sys_enter_execve")
def hello(ctx: c_void_p) -> c_int32:
print("entered")
print("multi constant support")
return c_int32(0)
@bpf
@section("tracepoint/syscalls/sys_exit_execve")
def hello_again(ctx: c_void_p) -> c_int64:
print("exited")
key = 0
delta = 0
tsp = last().lookup(key)
if True:
delta = ktime()
ddelta = deref(delta)
if ddelta < 1000000000:
print("execve called within last second")
last().delete(key)
ts = ktime()
last().update(key, ts)
# st = "st"
# last().update(key, ts)
keena = 2 + 1
# below breaks
# keela = keena + 1
# TODO: binops evaluate but into a random register and dont get assigned.
keema = 8 * 9
keesa = 10 - 11
keeda = 10 / 5
# x = 3
# y = False
# if x > 0:
# if x < 5:
# print(f"we prevailed {x}")
# else:
# print(f"we did not prevail {x}")
# ts = ktime()
# last().update(key, ts)
#
# st = "st"
# last().update(key, ts)
#
# keena = 2 + 1
# # below breaks
# # keela = keena + 1
# keema = 8 * 9
# keesa = 10 - 11
# keeda = 10 / 5
return c_int64(0)
@bpf
@bpfglobal
def LICENSE() -> str:
return "GPL"
compile()